3x^2+4x-1563x=0

Solution for 3x^2+4x-1563x=0 equation:

3x^2+4x-1563x=0

We add all the numbers together, and all the variables

3x^2-1559x=0

a = 3; b = -1559; c = 0;
Δ = b2-4ac
Δ = -15592-4·3·0
Δ = 2430481
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2430481}=1559$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1559)-1559}{2*3}=\frac{0}{6}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1559)+1559}{2*3}=\frac{3118}{6}
=519+2/3
$